site+4

· **Site 4**

__Equation 1__ – 250 g of phenol, 230g of CO2 and unlimited sodium hydroxide is available
 * Equation 1:**

C6H6O + CO2 + NaOH ® C8H3O5Na3 + H2O (phenol) (carbon (sodium (intermediate) (water) dioxide) hydroxide)

C6H6O + 2(CO2) + 3(NaOH) ® C8H3O5Na3 + 3(H2O)

__Equation 2__ – Unlimited amount of sulfuric acid, but your yield is 97%
 * Equation 2:**

C8H3O5Na3 + H2SO4 ® C8H6O5 + Na2SO4 (intermediate (sulfuric (final (sodium from eq. 1 above) acid) product) sulfate)

2 C8H3O5Na3 + 3 H2SO4 --> 2 C8H6O5 + 3 Na2SO4